Question

10道一元一次方程带解

Answer 1

①2(x-2)-3(4x-1)=9(1-x)
2x-4-12x+3=9-9x
x=10
②11x+64-2x=100-9x
18x=36
x=2
③15-(8-5x)=7x+(4-3x)
15-8+5x=7x+4-3x
x=-3
④2(x-2)+2=x+1
2x-4+2=x+1
x=3
⑤4(x+2)=5(x-2)
4x+8=5x-10
x=18
⑥ 120-4(x+5)=25
120-4x-20=25
-4x=75
x=-75/4
⑦30x-10(10-x)=100
30x-100+10x=100
40x=200
x=5
⑧12.5-3x=6.5
6=3x
x=2
⑨7x+6=8-3x
10x=2
x=1/5
⑩1-4(x+3)=3(x+2)
1-4x-12=3x+6
-17=7x
x=-17/7