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原式
=
[
3^(1/2)]X[(3X4)^(1/6)]X[(2/3)^(1/3)]
=
[3^(1/2+1/6-1/3)]X[(2X2)^(1/6)]X[2^(1/3)]
=
[3^(1/3)]X[2^(1/6+1/6+1/3)]
=
[3^(1/3)]X[2^(2/3)]
=
[3^(1/3)]X[2^(1/3)]X[2^(1/3)]
=
(3X2X2)^(1/3)
=
12^(1/3)
不知道我这样写你是否能看懂,不过这已经是一步一步写到做后的结果了,希望你满意!
=
[
3^(1/2)]X[(3X4)^(1/6)]X[(2/3)^(1/3)]
=
[3^(1/2+1/6-1/3)]X[(2X2)^(1/6)]X[2^(1/3)]
=
[3^(1/3)]X[2^(1/6+1/6+1/3)]
=
[3^(1/3)]X[2^(2/3)]
=
[3^(1/3)]X[2^(1/3)]X[2^(1/3)]
=
(3X2X2)^(1/3)
=
12^(1/3)
不知道我这样写你是否能看懂,不过这已经是一步一步写到做后的结果了,希望你满意!
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