Question

先化简(x-1分之x+1+1)÷x^2-2X+1分之x^2+x

Answer 1

先化简(x-1分之x+1+1)÷x^2-2X+1分之x^2+x

解：
原式=【(x+1)/(x-1)+1】÷(x^2+x)/(x^2-2x+1)
=(x+1+x-1)/(x-1)÷x(x+1)/(x-1)^2
=2x/(x-1)*(x-1)^2/x(x+1)
=2(x-1)/(x+1)

化简 2x^2+2x分之x-1÷x^2-1分之x^2-2x+1-x分之1

解：(x-1)/(2x^2+2x)÷(x^2-2x+1)/(x^2-1)-1/x
=(x-1)/〔2x(x+1)〕×(x+1)（x-1）/(x-1)^2-1/x
=(x-1)/〔2x(x+1)〕×(x+1)/(x-1)-1/x
=1/2x-1/x
=1/2x-2/2x
=-1/2x

先化简，要过程(x-1分之1-x+1分之1)除以2x平方-2分之x

(x-1分之1-x+1分之1)除以2x平方-2分之x=（x+1)(x-1）分之2/2分之x（4x-1）=4/(x+1)(x-1)x(4x-1)

化简（x-1）分之（x²-2x）÷【（x+1）分之（2x-1）-x+1】

原式=x(x-2)/(x-1)÷[（2x-1+1-x^）/(x+1)]
=x(x-2)/(x-1)×（x+1)/[-x(x-2)]
=-(x+1)/(x-1).

化简:2012天津(x-1)2分之x-x2-2x+1分之1

（2x²+x-2）/（2（2x+1））

化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1

原式=（x+1）/（x-1）-x(x-2)/(x+1)(x-1)÷(x-2)(x+1)/(x+1)²
=（x+1）/(x-1)-x/(x-1)
=(x+1-x)/(x-1)
=1/(x-1)
请好评

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若X^2+Y^2+2X-6Y+10=0，先化简X+Y分之Y^2，分之X-Y分之X-1

X^2+Y^2+2X-6Y+10=0
(x²+2x+1)+(y²-6y+9)=0
(x+1)²+(y-3)²=0
x=-1,y=3
(X+Y)分之Y^2=3²/(-1+3)=9/2
(X-Y)分之(X-1)=(-1-1)/(-1-3)=1/2
要化简的分不出分子分母,把x=-1,y=3代入计算就可以了,有疑问请追问

化简:2012天津(x-1)2分之x-x2-2x+1分之1 快

追问 分式方程:x分之480-2x分之600=45
要有过程
对不起，没有分了480/X-600/2X=45(480-600/2)1/x=45180=45X X=4

化简(x^2-2x+1)/(x^2+1)÷(x-1)/(x^2+x)-x

你是不是搞错了一个符号
(x^2-2x+1)/(x^2 - 1)÷(x-1)/(x^2+x)-x
=(x-1)²/(x+1)(x-1)×x(x+1)/(x-1)-x
=x-x
=0

(x^2-2x+1)/(x^2+1)÷(x-1)/(x^2+x)-x
=(x-1)²/(x²+1) ×x(x+1)/(x-1) -x
=x(x+1)(x-1)/(x²+1) -x
=x(x²-1)/(x²+1) -x(x²+1)/(x²+1)
=-2x/(x²+1)

先化简在求值：x-1分之x2-1+x（1+x分之1）其中x=（根号2）-1

（x^2-1)/(x-1)+x(1+1/x)
=x+1+x+1
=2(√2-1)+2
=2√2