Question

Cu2+与过量的氨水反应形成深蓝色溶液的离子方程式?

Answer 1

更新1:

Cu(OH)2(s) + 4NH3(aq) → [Cu(NH3)4]2+(aq) + 2OH-(aq) 我唔明白点解会个方程式咁样.. 点解会有4个NH3..

更新2:

其实我系唔明点解有边有4个

Cu(OH)2(s) + 4NH3(aq) → [Cu(NH3)4]2+(aq) + 2OH-(aq) 左边4个NH3系要平衡方程
因为原子不会无原无故地出现或消失. 右边有4个NH3 :[Cu(NH3)4]
自然左边也要有
不然的话就不平衡了. 2009-07-23 11:01:53 补充： 一条化学方程里
左右的原子数一定要一样 即左边有1个Cu
右边也只可以有一个Cu 右边有(NH3)4
即4*NH3
那左边也要有4个NH3 如果只列出参与的化学元数而不列出数目
就如这样: N2+H2→NH3 人家就会质疑: 另一个N去了那?为何多了一个H
从哪来的? (正确为: 2N2+3H2→2NH3)
if you are a CE level student
five me to say that there is nothing to understand. It is a matter of fact. So
you can only remember it. If you are a very good CE or a AL student : First of all
there are NH3 molecules in ammonia water i.e. NH3 (aq) Then
Cu is a trition metal and there are many more vacant orbitals in which the lone pair electrons of NH3 can form a dative bond i.e. bind to Cu2+ if you want to know why there are FOUR. try to write the s
p
d
f box diagram of Cu2+ and you will see.