高数求极限 几个小问题~~帮下忙
1.LimX趋向0,SIN5X^2/(TAN2x)^22.LimX趋向PAiSINX/X-PAI3LimX趋向正无穷,2^x*SIN1/2^X大家不要嘲笑我-,-谢谢了...
1.Lim X趋向0,SIN5X^2/(TAN2x)^2
2.Lim X趋向PAi SINX/X-PAI
3 Lim X趋向正无穷,2^x*SIN 1/2^X
大家不要嘲笑我-,-谢谢了 展开
2.Lim X趋向PAi SINX/X-PAI
3 Lim X趋向正无穷,2^x*SIN 1/2^X
大家不要嘲笑我-,-谢谢了 展开
1个回答
展开全部
lim(x->0) sin5x^2/(tan2x)^2 【等价无穷小替换:sint~t,tant~t】
①=lim(x->0) 5x^2/(2x)^2
=5/4
②=lim(x->0) sin5x^2/[sin2x/cos2x]^2
=lim(x->0) [sin5x^2/5x^2]* 5/4*[[2x/sin2x]^2]*[cos2x]^2
=5/4
①lim(x->π) sinx/(x-π) 【0/0 ,罗必塔法则】
=lim(x->π) cosx/1
=-1
②lim(x->π) sinx/(x-π) 【令:π-x = t】
=lim(t->0) sin(π-t)/(-t)
=-lim(t->0) sint/t
=-1
①lim(x->+∞) 2^x*sin(1/2^x) 【等价无穷小替换:x->+∞, 1/2^x ->0, sin(1/2^x)~1/2^x】
=lim(x->+∞) 2^x*(1/2^x)
=1
②lim(x->+∞) 2^x*sin(1/2^x)
=lim(x->+∞) sin(1/2^x) /[1/2^x] 【令:1/2^x=t】
=lim(t->0) sint/t
=1
①=lim(x->0) 5x^2/(2x)^2
=5/4
②=lim(x->0) sin5x^2/[sin2x/cos2x]^2
=lim(x->0) [sin5x^2/5x^2]* 5/4*[[2x/sin2x]^2]*[cos2x]^2
=5/4
①lim(x->π) sinx/(x-π) 【0/0 ,罗必塔法则】
=lim(x->π) cosx/1
=-1
②lim(x->π) sinx/(x-π) 【令:π-x = t】
=lim(t->0) sin(π-t)/(-t)
=-lim(t->0) sint/t
=-1
①lim(x->+∞) 2^x*sin(1/2^x) 【等价无穷小替换:x->+∞, 1/2^x ->0, sin(1/2^x)~1/2^x】
=lim(x->+∞) 2^x*(1/2^x)
=1
②lim(x->+∞) 2^x*sin(1/2^x)
=lim(x->+∞) sin(1/2^x) /[1/2^x] 【令:1/2^x=t】
=lim(t->0) sint/t
=1
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询