展开全部
因式分解吗?
3x²+4y²+3z²+8xy-8yz-10xz
=(3x^2 + 8xy + 4y^2) - (9xz + 6zy) - (xz + 2yz) + 3z^2
=(x+2y)(3x+2y) - 3z(3x+2y) - z(x+2y) + 3z^2
=(3x+2y)[(x+2y)-3z] - z[(x+2y)-3z]
=(3x+2y)(x+2y-3z) - z(x+2y-3z)
=(x+2y-3z)[(3x+2y)-z]
=(x+2y-3z)(3x+2y-z)
3x²+4y²+3z²+8xy-8yz-10xz
=(3x^2 + 8xy + 4y^2) - (9xz + 6zy) - (xz + 2yz) + 3z^2
=(x+2y)(3x+2y) - 3z(3x+2y) - z(x+2y) + 3z^2
=(3x+2y)[(x+2y)-3z] - z[(x+2y)-3z]
=(3x+2y)(x+2y-3z) - z(x+2y-3z)
=(x+2y-3z)[(3x+2y)-z]
=(x+2y-3z)(3x+2y-z)
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询