Question

解下列方程！要具体步骤！

0.1x²-1.2=0.4x
1/2x²+7/2x+5=0
4(x-2)²=x(x-2)
还有两道。。。。
2x²+x-3=0
16x²=9(x+1)²

Answer 1

(1)0.1x²-1.2=0.4x
x²-12=4x
x²-4x+4=16
(x-2)^2=(±4)^2
x-2=±4
x=6,或x=-2
(2)1/2x²+7/2x+5=0
x²+7x+10=0
(x+5)(x+2)=0
x=-5或x=-2
(3)4(x-2)²=x(x-2)
4x²-16x+16=x²-2x
3x²-14x+16=0
(3x-8)(x-2)=0
x=8/3或x=2

Answer 2

1。0.1x²-1.2=0.4x
x² -4x -12 =0
(x-4)(x+3)=0
x1=4，x2=-3
2。1/2x²+7/2x+5=0
x² -7x+10 =0
（x-5)(x-2)=0
x1=5，x2=2
3。4(x-2)²=x(x-2)
4x²-8x+16=x²-2x
3x² -6x+16=0

Answer 3

1。0.1x²-1.2=0.4x
x² -4x -12 =0
(x-4)(x+3)=0
x1=4，x2=-3
2。1/2x²+7/2x+5=0
x² -7x+10 =0
（x-5)(x-2)=0
x1=5，x2=2
3。4(x-2)²=x(x-2)
4x²-8x+16=x²-2x
3x² -6x+16=0
4,2x²+x-3=0
(2x+3)(x-1)=0
x1=-3/2;x2=1;
5,16x²=9(x+1)²
(4x+3x+3)(4x-3x-3)=0
x1=-3/7;x2=3;