已知集合A={x|x∈N,12/(6-x)∈N},用列举法表示集合A 过程!!!!
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12/(6-x)∈N
=> 12 = (6-x) m , where m is +ve integer
x = 6 -12/m < 6
x =1, m = -6 (rejected)
x=2, m = 3
x=3, m = 4
x=4, m= 3
x=5, m= 12
A={2,3,4,5}
=> 12 = (6-x) m , where m is +ve integer
x = 6 -12/m < 6
x =1, m = -6 (rejected)
x=2, m = 3
x=3, m = 4
x=4, m= 3
x=5, m= 12
A={2,3,4,5}
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