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y-x=e^(xy)隐函数求导?
1个回答
展开全部
y-x=e^(xy)
d/dx (y-x)=d/dx e^(xy)
dy/dx -1 = e^(xy) . ( x.dy/dx +y)
[1- xe^(xy)]dy/dx = 1+y.e^(xy)
dy/dx =[1+y.e^(xy)]/[1- xe^(xy)]
d/dx (y-x)=d/dx e^(xy)
dy/dx -1 = e^(xy) . ( x.dy/dx +y)
[1- xe^(xy)]dy/dx = 1+y.e^(xy)
dy/dx =[1+y.e^(xy)]/[1- xe^(xy)]
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