Question

利用两个线性表LA和LB分别表示两个集合A和B，现要求一个新的集合A=A并B。 算法是 void union(List &La,Lis

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<malloc.h>
typedef int status;
typedef int ElemType;
#define TRUE 1
#define ERROR 0
#define FALSE 0
#define OK 1
#define OVERFLOW -2
#define list_init_size 100
#define listincrement 10
typedef struct{
ElemType *elem;
int length;
int listsize;
}sqlist;
status equal(ElemType a,ElemType b)
{if(a==b)
return TRUE;
else
return FALSE;
}
int listlength(sqlist l)
{ return l.length;}
status listinsert(sqlist *l,int i,ElemType e)
{
ElemType *newbase,*q,*p;
if(i<1||i>(*l).length+1)
return ERROR;
if((*l).length>=(*l).listsize){
newbase=(ElemType*)realloc((*l).elem,((*l).listsize+listincrement)*sizeof(ElemType));
if(!newbase) exit(OVERFLOW);
(*l).elem=newbase;
(*l).listsize+=listincrement;
}
q=&((*l).elem[i-1]);
for(p=&((*l).elem[(*l).length-1]);p>=q;--p)
*(p+1)=*p;
*q=e;
++(*l).length;
return OK;
}
status initlist(sqlist *l){
(*l).elem=(ElemType*)malloc(list_init_size*sizeof(ElemType));
if(!(*l).elem)
exit(OVERFLOW);
(*l).length=0;
(*l).listsize=list_init_size;
return OK;
}
status getelem(sqlist l,int i,ElemType *e)
{ if(i<1||i>l.length)
exit(ERROR);
*e=*(l.elem+i-1);
return OK;
}
int LocateElem(sqlist L,ElemType e,status(*compare)(ElemType,ElemType))
{
ElemType *p;
int i=1;
p=L.elem;
while(i<=L.length&&!compare(*p++,e))
++i;
if(i<=L.length)
return i;
else
return 0;
}
void print(ElemType *c)
{
printf("%d ",*c);
}
status ListTraverse(sqlist l,void(*vi)(ElemType *))
{
ElemType *p;
int i;
p=l.elem;
for(i=1;i<=l.length;i++)
vi(p++);
printf("\n");
return OK;
}
void Union(sqlist *la,sqlist lb)
{
int la_len,lb_len;
int i;
ElemType e;
la_len=listlength(*la);
lb_len=listlength(lb);
for(i=1;i<=lb_len;i++)
{ getelem(lb,i,&e);
if(!LocateElem(*la,e,equal))
listinsert(la,++la_len,e);
}
}
void main()
{
sqlist la,lb;
int j,i;
i=initlist(&la);
if(i==1)
for(j=1;j<=6;j++)
i=listinsert(&la,j,j);
printf("la= ");
ListTraverse(la,print);
initlist(&lb);
for(j=1;j<=5;j++)
i=listinsert(&lb,j,2*j);
printf("lb= :");
ListTraverse(lb,print);
Union(&la,lb);
printf("la :");
ListTraverse(la,print);
}