Question

4(X+1)^2-9(2X-1)^=0最好用因式方程解，或者其它简便的方法!谢谢大帅哥和大MM了！！

希望你们能够把答案回答详细点，能够让我懂，谢谢了

Answer 1

4X^2+4+8X-36X^2-9+36X=0
-32X^2-5+44x=0
32X^2-44x+5=0
(4x-5)(8x-1)=0

解得x=5/4 , 1/8

Answer 2

4(X+1)^2-9(2X-1)^2=0
[2(x+1)]^2-[3(2x-1)]^2=0
(2x+2)^2-(6x-3)^2=0
(2x+2-6x+3)(2x+2+6x-3)=0
(5-4x)(8x-1)=0
5-4x=0或8x-1=0
x=5/4或x=1/8

Answer 3

看你那么好学，真的想弄懂，而不是答案。就写详细点吧

[2(x+1)]^2-[3(2x-1)]^2=0
平方差公式： [2(x+1)-3(2x-1)]*[2(x+1)+3(2x-1)]=0
=>>> (-4x+4)(8x-1)=0 =>(x-1)(8x-1)=0
则有：x-1=0, x=1;
8x-1=0 x=1/8