Question

编程 鸡兔同笼问题。已知鸡和兔的总数量，鸡腿和兔腿的总数量，求鸡和兔各多少只。

pascal编，用顺序结构

Answer 1

假设有head个头和foot只脚 程序如下：
#include<stdio.h>
void main()
{int i,head,foot,rabbit,chick;
printf("Enter the 2 numbers :");
scanf("%d%d",&head,&foot);
printf("head=%d,foot=%d\n",head,foot);
for(i=0;i<=head;i++)
{rabbit=i;
chick=head-rabbit;
if(rabbit*4+chick*2==foot)
printf("rabbit=%d,chick=%d\n",rabbit,chick);
}
}

Answer 2

这

Answer 3

var
a,b,i,j:integer;
begin
write('rabbit+chicken=');readln(a);
write('legs=');readln(b);
for i:=1 to a do
begin
j:=a-i;
if (i*2+j*4=b) then writeln('chicken=',i,' rabbit=',j);
end;
readln;
end.
试过了。

Answer 4

i是头j是脚
x是兔y是鸡
program jitutonglong;
var x,y,i,j:integer;
begin
read(i,j);
x:=(j-2*i)div 2;
y:=i-x;
writeln(x,' ',y)
end.

Answer 5

用2元1次方程做就行了