Question

数学题 用因式分解法解下列方程

(x+3)²=9(1-2x)²

Answer 1

解：(x+3)²=9(1-2x)²
（x+3）² -3² (1-2x)²=0
(x+3+3-6x)(x+3-3+6x)=0
(-5x+6)7x =0
所以x1=0 x2=6/5

Answer 2

(x+3)²=9(1-2x)²
(x+3)²-9(1-2x)²=0
(x+3+3-6x)(x+3-3+6x)=0
(6-3x)*7x=0
x=2或者 x=0

Answer 3

(x+3)²=9(1-2x)²
(x+3)²-[3(1-2x)]²=0
[(x+3)+3(1-2x)][(x+3)-3(1-2x)]=0
(-5x+6)(7x)=0
x1=6/5,x2=0

Answer 4

（x+3）^2=9(1-2x)^2

(x+3)^2-9(1-2x)^2=0

(x+3)^2-3^2(1-2x)^2=0

(x+3)^2-{3(1-2x)}^2=0

(x+3)^2-(3-6x)^2=0

(x+3-3+6x)(x+3+3-6x)=0

7x*(6-5x)=0

则，x=0或1.2