因式分解9a三次方-12a平方+ 3a=？
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9a³-12a+3a
=3a(3a²-4a+1)
=3a(a-1)(3a-1)
by⁵-by⁴+by-b
=b(y⁵-y⁴+y-1)
=b[y⁴(y-1)+(y-1)]
=b(y-1)(y⁴+1),1,9a三次方-12a平方+3a
=9a三次方-9a平方-3a平方+3a
=9a平方(a-1)-3a(a-1)
=3a(a-1)(3a-1)
by五次方-by四次方+by-b
=b[y四次方(y-1)+(y-1)]
=b(y-1)(y四次方+1),2,9a^3-12a^2+3a=3a(3a^2-4a+1)=3a(a-1)(3a-1)
by^5-by^4+by-b=by^4(y-1)+b(y-1)=b(y-1)(y^4+1),0,因式分解9a三次方-12a平方+ 3a=
by五次方-by四次方+by-b
=3a(3a²-4a+1)
=3a(a-1)(3a-1)
by⁵-by⁴+by-b
=b(y⁵-y⁴+y-1)
=b[y⁴(y-1)+(y-1)]
=b(y-1)(y⁴+1),1,9a三次方-12a平方+3a
=9a三次方-9a平方-3a平方+3a
=9a平方(a-1)-3a(a-1)
=3a(a-1)(3a-1)
by五次方-by四次方+by-b
=b[y四次方(y-1)+(y-1)]
=b(y-1)(y四次方+1),2,9a^3-12a^2+3a=3a(3a^2-4a+1)=3a(a-1)(3a-1)
by^5-by^4+by-b=by^4(y-1)+b(y-1)=b(y-1)(y^4+1),0,因式分解9a三次方-12a平方+ 3a=
by五次方-by四次方+by-b
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