在298K、100kPa时,已知:2H2O(g)=O2(g)+2H2(g)△H1?
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解题思路:设2H 2O(g)=O 2(g)+2H 2(g)△H 1 …①
Cl 2(g)+H 2(g)=2HCl(g )△H 2…②
2Cl 2(g)+2H 2O(g)=4HCl(g)+O 2(g)△H 3…③
由盖斯定律可知,③=①+2×②分析.
设2H2O(g)=O2(g)+2H2(g)△H1 …①
Cl2(g)+H2(g)=2HCl(g )△H2…②
2Cl2(g)+2H2O(g)=4HCl(g)+O2(g)△H3…③
由盖斯定律可知,③=①+2×②,因此△H3=△H1+2△H2.
故选A.
,10,在298K、100kPa时,已知:2H 2O(g)=O 2(g)+2H 2(g)△H 1
Cl 2(g)+H 2(g)=2HCl(g )△H 2
2Cl 2(g)+2H 2O(g)=4HCl(g)+O 2(g)△H 3
则△H 3与△H 1和△H 2间的关系正确的是( )
A. △H 3=△H 1+2△H 2
B. △H 3=△H 1+△H 2
C. △H 3=△H 1-2△H 2
D. △H 3=△H 1-△H 2
Cl 2(g)+H 2(g)=2HCl(g )△H 2…②
2Cl 2(g)+2H 2O(g)=4HCl(g)+O 2(g)△H 3…③
由盖斯定律可知,③=①+2×②分析.
设2H2O(g)=O2(g)+2H2(g)△H1 …①
Cl2(g)+H2(g)=2HCl(g )△H2…②
2Cl2(g)+2H2O(g)=4HCl(g)+O2(g)△H3…③
由盖斯定律可知,③=①+2×②,因此△H3=△H1+2△H2.
故选A.
,10,在298K、100kPa时,已知:2H 2O(g)=O 2(g)+2H 2(g)△H 1
Cl 2(g)+H 2(g)=2HCl(g )△H 2
2Cl 2(g)+2H 2O(g)=4HCl(g)+O 2(g)△H 3
则△H 3与△H 1和△H 2间的关系正确的是( )
A. △H 3=△H 1+2△H 2
B. △H 3=△H 1+△H 2
C. △H 3=△H 1-2△H 2
D. △H 3=△H 1-△H 2
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