Question

解一个一元二次方程！！！！

6x^2-0.8x+0.02=0。知道等于0.1 求过程。

Answer 1

6x²-0.8x+0.02=0
3x²-0.4x+0.01=0
3x²-0.1x-0.3x+0.01=0
x(3x-0.1)-0.1(3x-0.1)=0
(3x-0.1)(x-0.1)=0
x=0.1/3,x=0.1
即x=1/30,x=0.1

Answer 2

6x^2-0.8x+0.02=0
600X^2-80X+2=0
300X^2-40X+1=0
300(X-1/10)(X-1/30)=0

所以 X=1/10 或 X=1/30

Answer 3

(3x-0.1)(2x-0.2)=0
x1=1/30
x2=1/10

Answer 4

(x-0.1)*(x-0.1/3)=0

Answer 5

6x^2-0.8x+0.02=0
6x^2-4/5x+1/50=0
300x^2-40x+1=0
(10x-1)(30x-1)=0
10x-1=0 x=1/10=0.1
30x-1=0 x=1/30

Answer 6

是两个解吧，百度一下二次元方程解法你就会了，楼主初一？