Question

解方程64(2x-1)的平方=25

Answer 1

(2x-1)%e5%b9%b3%e6%96%b9%3d9(x%2b2)%e5%b9%b3%e6%96%b9%0d%0a%e4%b8%a4%e8%be%b9%e5%bc%80%e6%96%b9%ef%bc%9a2x-1%3d%e6%ad%a3%e8%b4%9f3%ef%bc%88x%2b2%ef%bc%89%0d%0a%e6%89%80%e4%bb%a5(1) 2x-1%3d%e8%b4%9f3%ef%bc%88x%2b2%ef%bc%89%0d%0a 2x-1%3d-3x-6%0d%0a x%3d-1%0d%0a (2) 2x-1%3d3%ef%bc%88x%2b2%ef%bc%89%0d%0a x%3d-7%0d%0a%e6%89%80%e4%bb%a5x1%3d-1%2cx2%3d-7 %0d%0a

Answer 2

解：原式为：
64（2x-1）²=25
64（2x-1）²-25=0
（16x-8）²-5²=0
（16x-8+5)（16x-8-5)=0
16x-3=0或16x-13=0
x=3/16或x=13/16