要过程 谢谢!m^2-1分之m^2-2m+1/(m-1-m+1/m-1),其中m=根号3 先化简再求值？
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(m^2-2m+1)/（m^2-1)÷[(m-1)-(m-1)/(m+1)]
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-m)]/(m+1)}
=(m-1)/(m+1)÷{m(m-1)/(m+1)}
=(m-1)/(m+1)*(m+1)/[m(m-1)]
=1/m
=1/√3
=√3/3,5,
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-m)]/(m+1)}
=(m-1)/(m+1)÷{m(m-1)/(m+1)}
=(m-1)/(m+1)*(m+1)/[m(m-1)]
=1/m
=1/√3
=√3/3,5,
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