Question

几道特别简单的初二的数学计算题，数学高手请进！

①(3x²y³)²÷(1/3xy²)²-7xy²
②(1/2-π/3)^0+(1/2)³×(-8)+2013²-2014²
③-2014×2010
④1999²
求详细解题过程！谢谢！

Answer 1

1.27x4y6*9x2y4-7xy2=243x6y10-7xy2
2.1+(-1)+(2013-2014)(2013+2014)=-4027
3.-(2012+2)(2012-2)=-2012²+4=-（2000+12）²+4=-4000000-48000-144+4=-4048140
4.（2000-1）²=4000000-4000+1=3996001

Answer 2

①(3x²y³)²÷(1/3xy²)²-7xy²
=﹙3x²y³÷1/3xy²﹚²-7xy²
=﹙9xy﹚²-7xy²

=81x²y²-7xy²
=xy²﹙81x-7﹚
②(1/2-π/3)^0+(1/2)³×(-8)+2013²-2014²
=1+1／8×(-8)+﹙2013+2014﹚﹙2013-2014﹚
=1-1-4027
=4027
③-2014×2010
=-﹙2012+2﹚﹙2012-2﹚
=-﹙2012²-2²﹚
=-﹙4048144-4﹚
=-4048140
④1999²=﹙2000-1)²=2000²-2x2000x1+1=4000000-4000+1=3996001

Answer 3

1题=X²Y²-7XY²
2题=1+1/8X(-8)+(2013+2014)(2013X2014)=1-1+(4027)X(-1)=-4027
3题=-(2012+2)(2012-2)=-(2012²-2X2)=-4048140
4题=（2000-1)²=2000²-2x2000x1-1=4000000-4000+1=3996001