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原式=√(a-1/a)²÷[(a-1)/a]x[1/(a+1)]
=(1/a- a)x [a/(a-1)] x [1/(a+1)]
=[(1-a²)/a] x[a/(a-1)] x [1/(a+1)]
=(1-a²)/[(a-1)(a+1)]
=(1-a²)/(a²-1)
=-1
=(1/a- a)x [a/(a-1)] x [1/(a+1)]
=[(1-a²)/a] x[a/(a-1)] x [1/(a+1)]
=(1-a²)/[(a-1)(a+1)]
=(1-a²)/(a²-1)
=-1
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