(2006?蚌埠二模)如图,在正方体ABCD-A1B1C1D1中,E是棱A1D1的中点,H为平面EDB内一点,HC1=(2m,-2m,
(2006?蚌埠二模)如图,在正方体ABCD-A1B1C1D1中,E是棱A1D1的中点,H为平面EDB内一点,HC1=(2m,-2m,-m)(m<0).(1)证明HC1⊥...
(2006?蚌埠二模)如图,在正方体ABCD-A1B1C1D1中,E是棱A1D1的中点,H为平面EDB内一点,HC1=(2m,-2m,-m)(m<0).(1)证明HC1⊥平面EDB;(2)求BC1与平面EDB所成的角;(3)若正方体的棱长为a,求三棱锥A-EDB的体积.
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证明:(1)设正方体的棱长为a,则
={
, 0 , a },
={ a , a , 0 }
∵
?
=0 ,
?
=0
∴
⊥
,
⊥
DE |
a |
2 |
DB |
∵
HC1 |
DE |
HC1 |
DB |
∴
HC1 |
DE |
HC1 |