Question

答案，过程先到先得财富值

Answer 1

(1) 4ab^2 - ab - 6ab^2 = -2ab^2 - ab
(2) xy + 5y^2 - 3 + 4xy - 5y^2 = 5xy - 3
(3) 2x^2 - 3y + 5xy + 7 + 1/6 x^2 - 3/4 y =13/6 x^2 + 5xy - 15/4 y + 7
(4) 4a^2 - 9a + 6 - 3a^2 + 8a - 5 = a^2 - a + 1
(5) 2x^2y - 5x^2 y + 2/3 x^2y + 5xy^2 = - 7/3 x^2y + 5xy^2
(6) 2a^2b - 4ab^2 - 4 + 5a^2b + 2ab^2 + 7 = 7a^2b - 4ab^2 + 3
(7) 6(a+2b) + 1/3 ( c - d) = 6a + 12b + 1/3 c - 1/3 d
(8) -5[3x - 2(3y - 4z)] = - 5[3x - 6y + 8z]
= - 15x + 30y - 40z
(9) 7(a^2b - ab) - 2(a^2b - 3ab) = 7a^2b - 7ab - 2a^2b + 6ab
= 5a^2b - ab
(10) 3(5a + 4) - 2(3a - 10) = 15a + 20 - 6a + 20
= 9a + 40

Answer 2

答案及过程如下 ：﹙1﹚.4ab²-ab-6ab²=-2ab²-ab, ﹙2﹚xy+5y²-3+4xy-5y²=5xy-3, ﹙3﹚2x²-3y+5xy+7+1/6 x²-3/4 y=13/6 x ²-15/4 y+5xy+7,﹙4﹚4a²-9a+6-3a²+8a-5＝a²-a+1, ﹙5﹚2x²y-5x²y+2/3 x²y+5xy²=-7/3 x²y+5xy², ﹙6﹚.2a²b-4ab²-4+5a²b+2ab²+7＝7a²b-2ab²+3 , ﹙7﹚-6﹙a+2b﹚+1/3﹙c-d﹚=-6a-12b+1/3 c-1/3 b, ﹙8﹚-5[3x-2﹙3y-4z﹚]=-5﹙3x-6y+8z﹚=-15x+30y-40z , ﹙9﹚7﹙a²b-ab﹚-2﹙a²b-3ab﹚=7a²b-7ab-2a²b+6ab=5a²b-ab, ﹙10﹚3﹙5a+4﹚-2﹙3a-10﹚=15a+12-6a+20=9a+32.