Question

C语言如何实现从txt中读取特定数据？

假设txt文件内容为以下格式
abcdef 123456//字母和数字之间用空格相分割
那么如何把abcdef和123456从文件中分别读入到
char ch[20]和int num这两个变量中?

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void main()
{
char *pcTmp = NULL;
char szBuf[] = "abcdef 123456";
char seps[] = " ";
char ch[20];
int num;

pcTmp = strtok(szBuf,seps);
if( NULL != pcTmp )
{
strcpy(ch, pcTmp);
printf("ch is %s\n", ch);
}
pcTmp = strtok(NULL,seps);
if( NULL != pcTmp )
{
num = atoi(pcTmp);
printf("num is %d\n", num);
}
system("pause");
}

追问

这个不对，是从一个文本文件中读

追答

一样的道理，你从文本读取无非是增加一个语句把文件的内容读到BUF中 然后再截取
#include
#include
#include
void main()
{
char *pcTmp = NULL;
char szBuf[20];
char seps[] = " ";
char ch[20];
int num;
FILE *fp;

fp = fopen("ABC.txt", "w");
if( NULL == fp)
return;
fwrite("abcdef 123456", 30, 1, fp);
fclose(fp);

fp = fopen("ABC.txt", "r");
if( NULL == fp)
return;
fread(szBuf, 30, 1, fp);
fclose(fp);
pcTmp = strtok(szBuf,seps);
if( NULL != pcTmp )
{
strcpy(ch, pcTmp);
printf("ch is %s\n", ch);
}
pcTmp = strtok(NULL,seps);
if( NULL != pcTmp )
{
num = atoi(pcTmp);
printf("num is %d\n", num);
}
system("pause");
}