2个回答
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配方:
1. X²+2X+3=(x+1)²+2
2. X²+2X-5=(x+1)²-6
3. 3X²+5X+4=3(x²-5x/烂困手3)²+4=3(x-5/尺誉6)²-3(5/6)²+4=3(x-5/6)²+23/12
4. 3X²+9X+4=3(x²+3x)+4=3(x+3/饥嫌2)²-3*3(3/2)²+4=3(x+3/2)²-11/4
5.2y-2y²-1
=-2y^2+2y-1
=-2(y^2-y)-1
=-2(y-1/2)^2+1/2-1
=-2(y-1/2)^2-1/2
1. X²+2X+3=(x+1)²+2
2. X²+2X-5=(x+1)²-6
3. 3X²+5X+4=3(x²-5x/烂困手3)²+4=3(x-5/尺誉6)²-3(5/6)²+4=3(x-5/6)²+23/12
4. 3X²+9X+4=3(x²+3x)+4=3(x+3/饥嫌2)²-3*3(3/2)²+4=3(x+3/2)²-11/4
5.2y-2y²-1
=-2y^2+2y-1
=-2(y^2-y)-1
=-2(y-1/2)^2+1/2-1
=-2(y-1/2)^2-1/2
展开全部
配方: 1. X2-2X-8=X2-2X+1-9
=(x-1)2-32
= [(x-1)+3][(x-1)-3]
= (x+2)(x-4)
2. X2+4X-5=X2+4X+4-9
=(x+2)2-32
= [(x+2)+3][(x+2)-3]
= (x+5)(x-1)
3. X2+6X+8
= (X2+6X+9)-1
=(x+3)2-12
= [(x+3)+1][(x+3)-1]
= (x+4)(x+2)
4
a2-4a-12
=a2-4a+4-16
=(a-2)2-16
=(a-2)2-42
=(绝森神a-2-4)*(并亏春宽a-2+4)
=(a-6)*(a+2)
5
2 y2- y -1
=(y2- y)+( y2- 1)
= y( y- 1)+ ( y+1) ( y- 1)
= ( y- 1)[ y+( y+1)]
= ( y- 1)( 2y+1)
=(x-1)2-32
= [(x-1)+3][(x-1)-3]
= (x+2)(x-4)
2. X2+4X-5=X2+4X+4-9
=(x+2)2-32
= [(x+2)+3][(x+2)-3]
= (x+5)(x-1)
3. X2+6X+8
= (X2+6X+9)-1
=(x+3)2-12
= [(x+3)+1][(x+3)-1]
= (x+4)(x+2)
4
a2-4a-12
=a2-4a+4-16
=(a-2)2-16
=(a-2)2-42
=(绝森神a-2-4)*(并亏春宽a-2+4)
=(a-6)*(a+2)
5
2 y2- y -1
=(y2- y)+( y2- 1)
= y( y- 1)+ ( y+1) ( y- 1)
= ( y- 1)[ y+( y+1)]
= ( y- 1)( 2y+1)
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