谁的导数是1/(x²-1)½
2个回答
展开全部
y'=ln [x+(1-x²)½ ]'=1/[x+(1-x²)½ ]× [x+(1-x²)½ ]‘
=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(1-x^2)’]
=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(-2x)]
=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(1-x^2)’]
=1/[x+(1-x²)½ ]× [1+1/2×(1-x²)½(-2x)]
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询