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∂z/∂x = {1/√[xy+√(x^2y^2+1)]} {(1/2)/√[xy+√(x^2y^2+1)]} [y+(1/2)2xy^2/√(x^2y^2+1)]
= (1/2)/[xy+√(x^2y^2+1)] [y+xy^2/√(x^2y^2+1)]
则 ∂z/∂y = (1/2)/[xy+√(x^2y^2+1)] [x+yx^2/√(x^2y^2+1)]
= (1/2)/[xy+√(x^2y^2+1)] [y+xy^2/√(x^2y^2+1)]
则 ∂z/∂y = (1/2)/[xy+√(x^2y^2+1)] [x+yx^2/√(x^2y^2+1)]
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