Question

数学问题求救

找出3个连续偶数，他们的和是最小的偶数加2倍的第二偶数等于20多过第三个偶数。

不会翻译= =请见谅...

附上英文..
find3 consecutive even integers so that the sum of the smallest and the twice the second is 20 more than the third.

Answer 1

三个偶数 x-2,x,x+2，
最小的与中间的数两倍的和比最大的多20，
x-2+2x=x+2+20
2x=24
x=12
所以，这三个数是10,12,14。

Answer 2

问题读不懂

Answer 3

2n,2(n+1),2(n+2)
2n+2*2(n+1)=20+2(n+2)
4n=20
n=5
10,12,14

Answer 4

设连续偶数a，b，c
the sum of the smallest and the twice the second is 20 more than the third.

最小偶数和第二小偶数的两倍之和比最大偶数大20
a+2=b
b+2=c
a+2b=c+20
a=10,b=12,c=14