Question

c语言,算术表达式的值,要具体程序 x+a%3*(int)(x+y)%2/4(设x=2.5,a=7,y=4.7) 拜托了，明天就要的

输出都没有,装什么高手啊!!不给分了!!

Answer 1

double Result(double x,int a,double y)
{
teturn x+a%3*(int)(x+y)%2/4;
}

int main()
{
double x=2.5;
double y=4.7;
int a=7;
double z = Result(x,a,y);
return 0;
}
z就是你要的结果。

Answer 2

#include <stdio.h>
int main()
{
double x,a,y;
scanf("%lf%lf%lf",&x,&a,&y);
fprintf("%lf", x+a%3*(int)(x+y)%2/4);
getchar();
getchar();
}

Answer 3

double func()
{
double x=2.5;
int a=7;
double y=4.7;
return x+a%3*(int)(x+y)%2/4;
}

Answer 4

main()
{
float x=2.5,y=4.7,s;
int a=7;
s=x+a%3*(int)(x+y)%2/4;
printf("%f",s);
}

Answer 5

台EASY了