Question

几个初二方程 求解

9x²-49=0
x^3-3=3/8
4(X+1)²-81=0
写过程谢谢。

Answer 1

9x²-49=0
9x^2=49,
x^2=49/9
x1=7/3,x2=-7/3

x^3-3=3/8
x^3=27/8,
x=3/2

4(X+1)²-81=0.
(x+1)^2=81/4
x+1=9/2,x+1=-9/2
x1=9/7,x2=-11/2

Answer 2

9x²-49=0
x²=49/9
x=7/3或x=-7/3

x^3-3=3/8
x³=3/8+3=27/8
x=3/2

4(X+1)²-81=0
(x+1)²=81/4
x+1=9/2或x+1=-9/2
x=7/2或x=-11/2

Answer 3

9x²-49=0
x^2=49/9 那么x=±7/3

x^3-3=3/8
x^3=27/8 那么x=3/2

4(X+1)²-81=0
(x+1)^2=81/4 (x+1)=±9/2 那么x=7/2或-11/2

Answer 4

1：9x²=49
x²=49/9
x=-7/3或 x=7/3

2： x^3=27/8
x=3/2

3：4(x+1)²=81
(x+1)²=81/4
x+1=±9/2
x=7/2或 x=-11/2

Answer 5

9x²-49=0
9x^2=49
x^2=49/9
x=7/3或-7/3

x^3-3=3/8
x^3=27/8
x=3/2

4(X+1)²-81=0
(x+1)^2=81/4
x+1=9/2或-9/2
x=7/2或-11/2