三角函数问题 sin50(1+√3tan10)的值
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1+√3tan10
=1+√3sin10/cos10
=(cos10+√3sin10)/cos10
=2sin(10+30)/cos10
=2sin40/cos10
sin50(1+√3tan10)
=(2sin40sin50)/cos10
=[cos(50-40)-cos(50+40)]/cos10
=cos10/cos10
=1
或者说:
sin50°(1+√3tan10°)
=2sin50°(cos60°cos10°+sin60°sin10°)/cos10°
=2sin50°cos50°/cos10°
=sin100°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1.
=1+√3sin10/cos10
=(cos10+√3sin10)/cos10
=2sin(10+30)/cos10
=2sin40/cos10
sin50(1+√3tan10)
=(2sin40sin50)/cos10
=[cos(50-40)-cos(50+40)]/cos10
=cos10/cos10
=1
或者说:
sin50°(1+√3tan10°)
=2sin50°(cos60°cos10°+sin60°sin10°)/cos10°
=2sin50°cos50°/cos10°
=sin100°/cos10°
=sin80°/cos10°
=cos10°/cos10°
=1.
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