有a²+1=a,则a²º²²+2022=?
展开全部
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
a^2+1=a
a^2 -a + 1/4 = -3/4
(a-1/2)^2 =-3/4
a = (1+√3i)/2 or (1-√3i)/2
a=cos(π/3)+isin(π/3) or cos(-π/3)+isin(-π/3)
a^2022
=cos(2022π/3)+isin(2022π/3) or cos(-2022π/3)+isin(-2022π/3)
=cosπ+isinπ or cos(-π)+isin(-π)
=-1
a^2022 +2022
=-1 +2022
=2021
a^2 -a + 1/4 = -3/4
(a-1/2)^2 =-3/4
a = (1+√3i)/2 or (1-√3i)/2
a=cos(π/3)+isin(π/3) or cos(-π/3)+isin(-π/3)
a^2022
=cos(2022π/3)+isin(2022π/3) or cos(-2022π/3)+isin(-2022π/3)
=cosπ+isinπ or cos(-π)+isin(-π)
=-1
a^2022 +2022
=-1 +2022
=2021
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
