
已知f(x)的定义域为【1,2】,求f(x的平方-1)的定义域 已知f(x的平方+3)的定义域为【3,7】,求fx同
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1.
1<=x^2-1<=2
2<=x^2<=3
所以,f(x的平方-1)的定义域:
根号2<=x<=根号3,及 -根号3<=x<=-根号2
即:[根号2,根号3]并[-根号3,-根号2]
2.
3<=x<=7
9<=x^2<=49
12<=x^2+3<=52
所以,f(x)的定义域:[12,52]
1<=x^2-1<=2
2<=x^2<=3
所以,f(x的平方-1)的定义域:
根号2<=x<=根号3,及 -根号3<=x<=-根号2
即:[根号2,根号3]并[-根号3,-根号2]
2.
3<=x<=7
9<=x^2<=49
12<=x^2+3<=52
所以,f(x)的定义域:[12,52]
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