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如果是:2/a-1除(2/a²-1加1/a+1),则:
[2/(a²-1)+1/(a+1)]÷2/(a-1)
=[2/(a+1)(a-1)+(a-1)/(a+1)(a-1)]×(a-1)/2
=(a+1)/(a+1)(a-1)×(a-1)/2
=1/2
如果是:2/a-1除以(2/a²-1加1/a+1),则:
2/(a-1)÷[2/(a²-1)+1/(a+1)]
=2/(a-1)×[(a+1)(a-1)/(a+1)]
=2/(a-1)×(a-1)
=2
[2/(a²-1)+1/(a+1)]÷2/(a-1)
=[2/(a+1)(a-1)+(a-1)/(a+1)(a-1)]×(a-1)/2
=(a+1)/(a+1)(a-1)×(a-1)/2
=1/2
如果是:2/a-1除以(2/a²-1加1/a+1),则:
2/(a-1)÷[2/(a²-1)+1/(a+1)]
=2/(a-1)×[(a+1)(a-1)/(a+1)]
=2/(a-1)×(a-1)
=2
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