Question

java 编写一个方法，求出数组中最小元素,不能调换数组原来的位置！急、、、跪求代码

Answer 1

int getMin(int []a) {
int min = a[0];
for(int i=1; i<a.length; i++) {
if(a[i]<min)
min = a[i];

}
return min;

}

参数类型和方法返回类型自己根据需要改变！

Answer 2

public static void main(String[] args)
{
System.out.println(findMin(new int[] { 2, 1231, 123, 123, 21, 231, }));
}

private static int findMin(int[] numbers)
{
assert (numbers.length > 0);
int min = numbers[0];

for (int i : numbers)
{
if (min < i)
min = i;
}

return min;
}

Answer 3

public int getMinNum(int[] dataArr)
{
int minData = dataArr[0];
for(int i=1;i<dataArr.length;i++){
minData = Math.min(minData,dataArr[i]);
}
return minData;
}
//传int类型的数组，可返回数组的最小值

Answer 4

public class MinIntNumber {
public static void main(String[] args){
int[] numbers = new int[]{5,3,6,1,7,9,21};
int min = getMinNumber(numbers);
System.out.println(min);
}

private static int getMinNumber(int[] numbers) {
//no parameter checking, please
int[] copy = Arrays.copyOf(numbers,numbers.length);
Arrays.sort(copy);
return copy[0];
}
}