计算:(-3/2)^2015*(2/3)^2014; (2/3)^2012*1.5^2013*(
-1)^2012;0.25^2014*4^2015-8^100*0.5^300;(0.125)^2015*(-8)^2014;(-2)^2010*(1/2)^2011;(...
-1)^2012;
0.25^2014*4^2015-8^100*0.5^300;
(0.125)^2015*(-8)^2014;
(-2)^2010*(1/2)^2011;
(-5a^6)^2-(-3a^3)^3*(-a^3)
最后一题可不回答 展开
0.25^2014*4^2015-8^100*0.5^300;
(0.125)^2015*(-8)^2014;
(-2)^2010*(1/2)^2011;
(-5a^6)^2-(-3a^3)^3*(-a^3)
最后一题可不回答 展开
1个回答
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(-3/2)^2015*(2/3)^2014
=(-3/2)^2014*(2/3)^2014*(-3/2)
=(3/2*2/3)^2014*(-3/2)=-3/2
(2/3)^2012*1.5^2013*(-1)^2012
=(2/3)^2012*1.5^2012*1.5*(-1)^2012
=(2/3*1.5)^2012*1.5*1
=1.5
=(-3/2)^2014*(2/3)^2014*(-3/2)
=(3/2*2/3)^2014*(-3/2)=-3/2
(2/3)^2012*1.5^2013*(-1)^2012
=(2/3)^2012*1.5^2012*1.5*(-1)^2012
=(2/3*1.5)^2012*1.5*1
=1.5
追答
0.25^2014*4^2015-8^100*0.5^300
=0.25^2014*4^2014*4-(2^3)^100*0.5^300
=(0.25*4)^2014*4-2^300*0.5^300
=4-(2*0.5)^300=3
(0.125)^2015*(-8)^2014
=(0.125)^2014*8^2014*0.125
=(0.125*8)^2014*0.125=0.125
(-2)^2010*(1/2)^2011
=2^2010*(1/2)^2010*1/2
=(2*(1/2))^2010*1/2=1/2
(-5a^6)^2-(-3a^3)^3*(-a^3)
=25a^12-(-27)a^9*(-a^3)
=25a^12-27a^(9+3)
=25a^12-27a^12=-2a^12
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