求答案,T^T
2014-08-28
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设∠A=x°
∵∠A=1/2∠C=1/2∠ABC
∴∠C=∠ABC=2∠A=2x°
∵∠A+∠ABC+∠C=180°
∴则有方程:
x+2x+2x=180
x=36
即∠A=36°
∵∠A=1/2∠C=1/2∠ABC
∴∠C=∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠BDC=∠A+∠ABD
∴∠BDC=72°
即∠A=36°,∠BDC=72°
∵∠A=1/2∠C=1/2∠ABC
∴∠C=∠ABC=2∠A=2x°
∵∠A+∠ABC+∠C=180°
∴则有方程:
x+2x+2x=180
x=36
即∠A=36°
∵∠A=1/2∠C=1/2∠ABC
∴∠C=∠ABC=72°
∵BD平分∠ABC
∴∠ABD=∠CBD=1/2∠ABC=36°
∵∠BDC=∠A+∠ABD
∴∠BDC=72°
即∠A=36°,∠BDC=72°
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