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多项式乘多项式,这题咋算? (3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)-3^32/2 加个解题过程,重赏!
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原式=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/(3-1)-3^32/2
=(3^2-1) (3^2+1)(3^4+1)(3^8+1) (3^16+1)/2-3^32/2
=(3^4-1)(3^4+1)(3^8+1) (3^16+1)/2-3^32/2
=(3^8-1)(3^8+1) (3^16+1)/2-3^32/2
=[3^32-1]/2-3^32/2
=-1/2
=(3^2-1) (3^2+1)(3^4+1)(3^8+1) (3^16+1)/2-3^32/2
=(3^4-1)(3^4+1)(3^8+1) (3^16+1)/2-3^32/2
=(3^8-1)(3^8+1) (3^16+1)/2-3^32/2
=[3^32-1]/2-3^32/2
=-1/2
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