
计算:(1)(14)-1-27+(5-π)0 (2)(2x-1)2+(x-2)(x+2)-4x(x-12
计算:(1)(14)-1-27+(5-π)0(2)(2x-1)2+(x-2)(x+2)-4x(x-12)...
计算:(1)(14)-1-27+(5-π)0 (2)(2x-1)2+(x-2)(x+2)-4x(x-12)
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(1)原式=4?3
+1,
=5?3
;
(2)原式=4x2-4x+1+x2-4-4x2+2x,
=x2-2x-3.
故答案为:(1)5?3
;(2)x2-2x-3.
3 |
=5?3
3 |
(2)原式=4x2-4x+1+x2-4-4x2+2x,
=x2-2x-3.
故答案为:(1)5?3
3 |
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