1个回答
展开全部
∫ (1-x)dx/√(9-4x^2) = ∫dx/√(9-4x^2) - ∫xdx/√(9-4x^2)
= (1/3) ∫dx/√[1-(2x/3)^2] - (1/2)∫d(x^2)/√(9-4x^2)
= (1/2) ∫ d(2x/3)/√[1-(2x/3)^2] + (1/8) ∫d(9-4x^2)/√(9-4x^2)
=............
= (1/3) ∫dx/√[1-(2x/3)^2] - (1/2)∫d(x^2)/√(9-4x^2)
= (1/2) ∫ d(2x/3)/√[1-(2x/3)^2] + (1/8) ∫d(9-4x^2)/√(9-4x^2)
=............
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
