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高二数学,画圈的题目 ,要过程,详细 100
1个回答
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∵y=sin4x+cos4x
=(sin2x+cos2x)2-2sin2xcos2x
=1-1/2×sin22x
=1-1/2×1xcos4x /2
=3/4+1/4 ×cos4x,
∴其周期T=2π/4=π/2,
∴答案为:π/2.
=(sin2x+cos2x)2-2sin2xcos2x
=1-1/2×sin22x
=1-1/2×1xcos4x /2
=3/4+1/4 ×cos4x,
∴其周期T=2π/4=π/2,
∴答案为:π/2.
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