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CuA = R-A
= R - {x|x≤1 or x≥3}
= { x| 1<x<3 }
B is subset of CuA
then
m > 1 and m+1 < 3
m > 1 and m < 2
=> 1<m< 2 #
= R - {x|x≤1 or x≥3}
= { x| 1<x<3 }
B is subset of CuA
then
m > 1 and m+1 < 3
m > 1 and m < 2
=> 1<m< 2 #
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