Question

Java在Dog1（）{}这一行出现Implicit super constructor Dog() is undefined. Must explicitly invoke

Java在Dog1（）{}这一行出现Implicit super constructor Dog() is undefined. Must explicitly invoke another constructor为什么

class Dog{
private String name;
private int number;
private String sex;
Dog(String name,int number ,String sex)
{
this.name=name;
this.number= number;
this.sex=sex;
}
public void dogg()
{
System.out.println("狗狗叫："+this.name);
System.out.println("狗狗的年龄"+this.number);
System.out.println("狗狗的性别"+this.sex);
}
}
class Dog1 extends Dog
{
Dog1(String name,int age ,String sex)
{
super(name,age,sex);
}
Dog1(){} //就是这行！！！！！！！！！！！！！！！！！！！！！
public void special()
{
System.out.println("dog1会啃骨头，把妹");
}
}

public class dogStore {
public static void main(String[] args)
{
Dog1 mydog1=new Dog1();
mydog1.special();
}
}

Answer 1

父类的无参数构造器没有显示写出来

Answer 2

错误原因：
没有为父类Dog定义无参数的构造函数
修改方法：
1，定义Dog(){}
2，在Dog1()中显示调用父类已定义的构造函数。
{
super("无名", -1, "未知");

}