学霸求解！！
1个回答
展开全部
从C和D分别向x轴作垂线，垂足分别为C'(5, 0), D'(2, 0)
AD' = 1, D'C' = 3, BC' = 2, CC' = 4, DD' = 5
四边形ABCD的面积 = △ADD'的面积 + 梯形CDD'C'的面积 + △BCC'的面积
= (1/2)*AD'*D'D + (1/2)*(CC'+DD')*D'C' + (1/2)*BC'*C'C
=(1/2)*1*5 + (1/2)*(4 + 5)*3 + (1/2)*2*4
= 5/2 + 27/2 + 4
= 20
AD' = 1, D'C' = 3, BC' = 2, CC' = 4, DD' = 5
四边形ABCD的面积 = △ADD'的面积 + 梯形CDD'C'的面积 + △BCC'的面积
= (1/2)*AD'*D'D + (1/2)*(CC'+DD')*D'C' + (1/2)*BC'*C'C
=(1/2)*1*5 + (1/2)*(4 + 5)*3 + (1/2)*2*4
= 5/2 + 27/2 + 4
= 20
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
