Question

C#在一个数组里找到相同的字符串

C#在一个spring数组里找出相同的字符串，比如
ArrayList mylist1 = new ArrayList(){"1b","1b","2t","3t","4t","5t","5t","6w","6w"};
找出后放到一个数组里，让数组得到ArrayList mylist2 = new ArrayList(){"1b","1b","5t","5t","6w","6w"};

Answer 1

X 表示以十六进制形式输出
02 表示不足两位，前面补0输出；出过两位，不影响
举例：
printf("%02X", 0x123); //打印出：123
printf("%02X", 0x1); //打印出：01

Answer 2

public void test()

{

ArrayList mylist1 = new ArrayList();

mylist1.Add("1b");

mylist1.Add("1b");

mylist1.Add("2t");

mylist1.Add("3t");

mylist1.Add("4t");

mylist1.Add("5t");

mylist1.Add("5t");

mylist1.Add("6w");

mylist1.Add("6w");

ArrayList temp = new ArrayList();

foreach(string s in mylist1)

{

int count = 0;

foreach(string v in mylist1)

{

if(v.Equals(s))

count = count + 1;

}

if(count > 1)

{

temp.Add(s);

}

}

foreach(string s in temp)

{

Report.Info(s + "       ");

}

}