求解这道数学题
1个回答
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A={x| x≤2 or x≥5 }
(2x-5)/(x+2)<1
(2x-5-x-2)/(x+2) <0
(x-7)/(x+2)<0
-2<x<7
B= { x| (2x-5)/(x+2)<1 } = { x| -2<x<7 }
C={x|a<x<a+1}
(1)
AUB
= {x| x≤2 or x≥5 } U { x| -2<x<7 }
=R
(CuA)∩B
={x| 2<x<5} ∩ { x| -2<x<7 }
={x| 2<x< 5 }
(2)
B∩C =C
=> C is subset of B
a>-2 and a+1<7
-2<a<6
(2x-5)/(x+2)<1
(2x-5-x-2)/(x+2) <0
(x-7)/(x+2)<0
-2<x<7
B= { x| (2x-5)/(x+2)<1 } = { x| -2<x<7 }
C={x|a<x<a+1}
(1)
AUB
= {x| x≤2 or x≥5 } U { x| -2<x<7 }
=R
(CuA)∩B
={x| 2<x<5} ∩ { x| -2<x<7 }
={x| 2<x< 5 }
(2)
B∩C =C
=> C is subset of B
a>-2 and a+1<7
-2<a<6
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