Question

Java如何获取JSON的内容

第一张图是需要获取的内容，我想要获取rsp，第二章图是我写的代码，我想的是String获取rsp，然后转成JSONArray，再迭代取出JSONObject，请问我这么写正确吗？
报错了A JSONArray text must start with '['

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Answer 1

如果不是Android开发环境的话，首先需要引入处理JSON数据的包：json-lib-2.2.3-jdk15.jar
Java样例程序如下：
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import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

public class DoJSON {
public static void main(String[] args) {
JSONArray employees = new JSONArray(); //JSON数组
JSONObject employee = new JSONObject(); //JSON对象

employee.put("firstName", "Bill"); //按“键-值”对形式存储数据到JSON对象中
employee.put("lastName", "Gates");
employees.add(employee); //将JSON对象加入到JSON数组中

employee.put("firstName", "George");
employee.put("lastName", "Bush");
employees.add(employee);

employee.put("firstName", "Thomas");
employee.put("lastName", "Carter");
employees.add(employee);

System.out.println(employees.toString());
for(int i=0; i<employees.size(); i++) {
JSONObject emp = employees.getJSONObject(i);
System.out.println(emp.toString());
System.out.println("FirstName :\t" + emp.get("firstName"));
System.out.println("LastName : \t" + emp.get("lastName"));
}
}
}
运行效果：
[{"firstName":"Bill","lastName":"Gates"},{"firstName":"George","lastName":"Bush"},{"firstName":"Thomas","lastName":"Carter"}]
{"firstName":"Bill","lastName":"Gates"}
FirstName : Bill
LastName : Gates
{"firstName":"George","lastName":"Bush"}
FirstName : George
LastName : Bush
{"firstName":"Thomas","lastName":"Carter"}
FirstName : Thomas
LastName : Carter

Answer 2

这样的用法不对，rsp是JSONArray格式数据，不能用getString取出，只能用JSONArray rsp = xml.getJSONArray("rsp")取出然后遍历

Answer 3

求采纳

public static void main(String[] args) {
	String json = "{\"xml\":{\"code\":\"0\",\"nonceStr\":\"EAGEGEGAWGWGWAGWAGWAG\",\"rsp\":[{\"aac02\":\"59682656655\"},{\"aac02\":\"59682656656\"},{\"aac02\":\"59682656657\"}]}}";
	JSONObject jsonObj = JSONObject.fromObject(json);
	JSONObject xml = jsonObj.getJSONObject("xml");
	System.out.println(xml);
	JSONArray rsp = xml.getJSONArray("rsp");
	List<DataRsp> list = new ArrayList<>();
	for (int i = 0; i < rsp.size(); i++) {
		DataRsp data = (DataRsp) JSONObject.toBean(rsp.getJSONObject(i),DataRsp.class);
		list.add(data);
	}
	System.out.println(list);
}

public class DataRsp {
	private String aac02;

	public String getAac02() {
		return aac02;
	}

	public void setAac02(String aac02) {
		this.aac02 = aac02;
	}

	@Override
	public String toString() {
		return "DataRsp [aac02=" + aac02 + "]";
	}
}