Question

java编程题 指出下面程序的运行错误，说明原因

public class OutClass{
private int varInOuterClass = 0;

public OutClass(){
}
public void callOutter(){
int varInOuterMethod = 0;
class InnerClass{
private int varInInnerClass = 0;
public InnerClass(){
}
public void print(){
System.out.println("varInOuterClass" + varInOuterClass);
System.out.println("varInInnerClass" + varInInnerClass);
System.out.println("varInInnerClass" + varInOuterMethod);
}
}
InnerClass inner = new InnerClass();
inner.print();
}
public static void main(String[] args){
OutClass out = new OutClass();
out.callOutter();
}
}

Answer 1

由于能力不够，我只能我运行一下，发现并没有错误。

这种写法我第一次见。