Question

(2㎡)-4(m+1)(m-3)≧0

(m-1)(m-3)+1
计算 分解因式
顺便把这一做了：x^2+x=0,试求2x^2+2x+2008的值

Answer 1

(m-1)(m-3)+1
=m^2-4m+3+1
=(m-2)^2
x^2+x=0,试求2x^2+2x+2008
2x^2+2x+2008=2(x^2+x)+2008=2008