求函数y=cos^3x-(x-1)/√x的微分
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y
=(cosx)^3-(x-1)/√x
=(cosx)^3-√x + x^(-1/2)
dy
= 3(cosx)^2. d(cosx)- (1/2)x^(-1/2) dx - (1/2)x^(-3/2) dx
= 3(cosx)^2. (-sinx dx)- (1/2)x^(-1/2) dx - (1/2)x^(-3/2) dx
=[-3sinx.(cosx)^2- (1/2)x^(-1/2)- (1/2)x^(-3/2) ]dx
=(cosx)^3-(x-1)/√x
=(cosx)^3-√x + x^(-1/2)
dy
= 3(cosx)^2. d(cosx)- (1/2)x^(-1/2) dx - (1/2)x^(-3/2) dx
= 3(cosx)^2. (-sinx dx)- (1/2)x^(-1/2) dx - (1/2)x^(-3/2) dx
=[-3sinx.(cosx)^2- (1/2)x^(-1/2)- (1/2)x^(-3/2) ]dx
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