Question

分别用循环和递归的方法来编写一个求n！的程序

用java语言 不是c语言

Answer 1

public class Test1 {

public static void main(String[] args) {
// 循环
int n = 5;
int mul1 = 1;
for (int i = 1; i <= n; i++) {
mul1 = mul1 * i;
}
System.out.println(mul1);

// 递归
int mul2 = 1;
mul2 = Test1.test(n);
System.out.println(mul2);

}

public static int test(int n) {
if (n == 1) {
return n;
} else {
return test(n - 1) *n;
}

}
}

Answer 2

public class Recur{ public Recur(){ recurMethod(1); } public void { count++; if(count>30) return; printf("正在进行第 %d 次递归!\n